An electron with rest mass m_{0} moves with a | vedclass

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(C) According to the theory of special relativity,the relativistic mass $m$ of an object moving with velocity $v$ is given by the formula:$m = \frac{m

Vedclass · Accepted Answer

$5m_0/3$

Vedclass · Answer

(C) According to the theory of special relativity,the relativistic mass $m$ of an object moving with velocity $v$ is given by the formula:$m = \frac{m_0}{\sqrt{1 - \frac{v^2}{c^2}}}$Given that the speed $v = 0.8 c$,we substitute this value into the equation:$m = \frac{m_0}{\sqrt{1 - \frac{(0.8c)^2}{c^2}}}$$m = \frac{m_0}{\sqrt{1 - 0.64}}$$m = \frac{m_0}{\sqrt{0.36}}$$m = \frac{m_0}{0.6}$$m = \frac{m_0}{6/10} = \frac{10}{6} m_0 = \frac{5}{3} m_0$Therefore,the mass of the electron at this speed is $\frac{5}{3} m_0$.

An electron with rest mass $m_{0}$ moves with a speed of $0.8 c$. Its mass when it moves with this speed is

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